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Doubt & Answer Explanation

Doubt

FIND THE NET FORCE ON THE CHARGE Q1 DUE TO THE OTHER THREE CHARGES AS SHOWN IN THE FIGURE. TAKE Q1= -5 μC;
Q2= -8μC
Q3=15μC
Q4= -16μC......

Hello sir,
  it's easy to find the net force ..... But how to find the components of the net force!!! how to determine the angle to find the components!!!!

Answer Explanation


Net force along x direction is:


Fx = -K(5)(8)/r(10-12)N + K(5)(16)/( r?2)2(10-12)(cos45o)N


Net force along y direction is:

Fy = -K(5)(15)/r(10-12)N + K(5)(16)/( r?2)2(10-12)(sin45o)N

The angle made by this force with the horizontal direction is ? such that tan? = Fy/Fx


The magnitude of the resultant force is (Fx2 + Fy2)1/2.


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