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Doubt

How many litres of oxygen at STP are required for the combustion of 4g of CH4 gas. calculate the volume of CO2 produced at STP.

Answer Explanation

4g of CH4 is 4/16 = 0.25 moles of methane.

CH4 + 2O2 --> CO2 + 2H2O

1 mole of methane requires 2 moles of oxygen, so 0.25 moles of CH4 require 0.5 moles of oxygen = 0.5 x 22.4 = 11.2 litres of oxygen at STP. This is because 1 mole of oxygen occupies 22.4 litres of volume at STP.

0.25 moles of CO2 are produced. Again, 0.25 moles of CO2 = 0.25 x 22.4 = 5.6 litres of CO2. So, 5.6 litres of carbon dioxide are produced.

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